3.43 \(\int \csc (c+d x) \sqrt {-a-a \sin (c+d x)} \, dx\)

Optimal. Leaf size=40 \[ \frac {2 \sqrt {a} \tan ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {a (-\sin (c+d x))-a}}\right )}{d} \]

[Out]

2*arctan(cos(d*x+c)*a^(1/2)/(-a-a*sin(d*x+c))^(1/2))*a^(1/2)/d

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Rubi [A]  time = 0.05, antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2773, 204} \[ \frac {2 \sqrt {a} \tan ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {a (-\sin (c+d x))-a}}\right )}{d} \]

Antiderivative was successfully verified.

[In]

Int[Csc[c + d*x]*Sqrt[-a - a*Sin[c + d*x]],x]

[Out]

(2*Sqrt[a]*ArcTan[(Sqrt[a]*Cos[c + d*x])/Sqrt[-a - a*Sin[c + d*x]]])/d

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 2773

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[(-2*
b)/f, Subst[Int[1/(b*c + a*d - d*x^2), x], x, (b*Cos[e + f*x])/Sqrt[a + b*Sin[e + f*x]]], x] /; FreeQ[{a, b, c
, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]

Rubi steps

\begin {align*} \int \csc (c+d x) \sqrt {-a-a \sin (c+d x)} \, dx &=\frac {(2 a) \operatorname {Subst}\left (\int \frac {1}{-a-x^2} \, dx,x,-\frac {a \cos (c+d x)}{\sqrt {-a-a \sin (c+d x)}}\right )}{d}\\ &=\frac {2 \sqrt {a} \tan ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {-a-a \sin (c+d x)}}\right )}{d}\\ \end {align*}

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Mathematica [B]  time = 0.08, size = 95, normalized size = 2.38 \[ \frac {\sqrt {-a (\sin (c+d x)+1)} \left (\log \left (\sin \left (\frac {1}{2} (c+d x)\right )-\cos \left (\frac {1}{2} (c+d x)\right )+1\right )-\log \left (-\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )+1\right )\right )}{d \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[c + d*x]*Sqrt[-a - a*Sin[c + d*x]],x]

[Out]

((-Log[1 + Cos[(c + d*x)/2] - Sin[(c + d*x)/2]] + Log[1 - Cos[(c + d*x)/2] + Sin[(c + d*x)/2]])*Sqrt[-(a*(1 +
Sin[c + d*x]))])/(d*(Cos[(c + d*x)/2] + Sin[(c + d*x)/2]))

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fricas [A]  time = 0.51, size = 221, normalized size = 5.52 \[ \left [\frac {\sqrt {-a} \log \left (\frac {a \cos \left (d x + c\right )^{3} - 7 \, a \cos \left (d x + c\right )^{2} + 4 \, {\left (\cos \left (d x + c\right )^{2} + {\left (\cos \left (d x + c\right ) + 3\right )} \sin \left (d x + c\right ) - 2 \, \cos \left (d x + c\right ) - 3\right )} \sqrt {-a \sin \left (d x + c\right ) - a} \sqrt {-a} - 9 \, a \cos \left (d x + c\right ) + {\left (a \cos \left (d x + c\right )^{2} + 8 \, a \cos \left (d x + c\right ) - a\right )} \sin \left (d x + c\right ) - a}{\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )^{2} + {\left (\cos \left (d x + c\right )^{2} - 1\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 1}\right )}{2 \, d}, \frac {\sqrt {a} \arctan \left (\frac {\sqrt {-a \sin \left (d x + c\right ) - a} {\left (\sin \left (d x + c\right ) - 2\right )}}{2 \, \sqrt {a} \cos \left (d x + c\right )}\right )}{d}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="fricas")

[Out]

[1/2*sqrt(-a)*log((a*cos(d*x + c)^3 - 7*a*cos(d*x + c)^2 + 4*(cos(d*x + c)^2 + (cos(d*x + c) + 3)*sin(d*x + c)
- 2*cos(d*x + c) - 3)*sqrt(-a*sin(d*x + c) - a)*sqrt(-a) - 9*a*cos(d*x + c) + (a*cos(d*x + c)^2 + 8*a*cos(d*x
+ c) - a)*sin(d*x + c) - a)/(cos(d*x + c)^3 + cos(d*x + c)^2 + (cos(d*x + c)^2 - 1)*sin(d*x + c) - cos(d*x +
c) - 1))/d, sqrt(a)*arctan(1/2*sqrt(-a*sin(d*x + c) - a)*(sin(d*x + c) - 2)/(sqrt(a)*cos(d*x + c)))/d]

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giac [B]  time = 0.68, size = 69, normalized size = 1.72 \[ -\frac {\sqrt {-a} \log \left (\frac {{\left | -2 \, \sqrt {2} + 4 \, \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}}{{\left | 2 \, \sqrt {2} + 4 \, \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}}\right ) \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="giac")

[Out]

-sqrt(-a)*log(abs(-2*sqrt(2) + 4*sin(-1/4*pi + 1/2*d*x + 1/2*c))/abs(2*sqrt(2) + 4*sin(-1/4*pi + 1/2*d*x + 1/2
*c)))*sgn(cos(-1/4*pi + 1/2*d*x + 1/2*c))/d

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maple [A]  time = 0.49, size = 69, normalized size = 1.72 \[ -\frac {2 \left (1+\sin \left (d x +c \right )\right ) \sqrt {a \left (\sin \left (d x +c \right )-1\right )}\, \sqrt {a}\, \arctan \left (\frac {\sqrt {a \left (\sin \left (d x +c \right )-1\right )}}{\sqrt {a}}\right )}{\cos \left (d x +c \right ) \sqrt {-a -a \sin \left (d x +c \right )}\, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x)

[Out]

-2*(1+sin(d*x+c))*(a*(sin(d*x+c)-1))^(1/2)*a^(1/2)*arctan((a*(sin(d*x+c)-1))^(1/2)/a^(1/2))/cos(d*x+c)/(-a-a*s
in(d*x+c))^(1/2)/d

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {-a \sin \left (d x + c\right ) - a} \csc \left (d x + c\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(-a*sin(d*x + c) - a)*csc(d*x + c), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {\sqrt {-a-a\,\sin \left (c+d\,x\right )}}{\sin \left (c+d\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((- a - a*sin(c + d*x))^(1/2)/sin(c + d*x),x)

[Out]

int((- a - a*sin(c + d*x))^(1/2)/sin(c + d*x), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {- a \left (\sin {\left (c + d x \right )} + 1\right )} \csc {\left (c + d x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))**(1/2),x)

[Out]

Integral(sqrt(-a*(sin(c + d*x) + 1))*csc(c + d*x), x)

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